20y^2+19y-6=0

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Solution for 20y^2+19y-6=0 equation:


Simplifying
20y2 + 19y + -6 = 0

Reorder the terms:
-6 + 19y + 20y2 = 0

Solving
-6 + 19y + 20y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(-6 + -5y)(1 + -4y) = 0

Subproblem 1

Set the factor '(-6 + -5y)' equal to zero and attempt to solve: Simplifying -6 + -5y = 0 Solving -6 + -5y = 0 Move all terms containing y to the left, all other terms to the right. Add '6' to each side of the equation. -6 + 6 + -5y = 0 + 6 Combine like terms: -6 + 6 = 0 0 + -5y = 0 + 6 -5y = 0 + 6 Combine like terms: 0 + 6 = 6 -5y = 6 Divide each side by '-5'. y = -1.2 Simplifying y = -1.2

Subproblem 2

Set the factor '(1 + -4y)' equal to zero and attempt to solve: Simplifying 1 + -4y = 0 Solving 1 + -4y = 0 Move all terms containing y to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -4y = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -4y = 0 + -1 -4y = 0 + -1 Combine like terms: 0 + -1 = -1 -4y = -1 Divide each side by '-4'. y = 0.25 Simplifying y = 0.25

Solution

y = {-1.2, 0.25}

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